2 goats, 1 car problem
I first saw this problem in NUMB3RS show. The Math genius shared how our instincts can be wrong in a Math for dummies class.
Imagine you are in a game show. There are 3 doors. Behind two of the doors, there is a goat. Behind one door, there’s a car. Your goal is to get a car.
You pick a door. And the host of the show who knows all the placements opens another door that has a goat behind it.
Now he asks you, "Do you want to change your answer?"
You might think that you have a 50/50 chance of being correct or the host could be manipulating you to change your answer.
In both scenarios you are wrong.
You are definitely wrong in thinking that you have a 50/50 chance. It's more than that if you switch.
The manipulation part, you might be right but still it's better if you switch.
Probability shifts when informed decisions are introduced.
Let me give you another scenario. I have arranged 52 cards, face down on a table. You have to pick a hard and ace of hearts is the winner.
You point at one of the cards, but you don’t look at it.
Then I who knows where the ace of hearts is, turns every card except your card and one other card.
And I ask you, "Do you want to change your answer?"
Again the odds here can look 50/50 but is it really?
Forced with the improbability of having picked the right card from the start, you will most likely switch.
Probability that you first picked the ace of hearts is 1.9% (1/52)
Probability that you didn't pick ace of hearts is 98.1% (51/52)
It also means that the probability of any of those cards being an ace of hearts is 98.1%
And when the host removed the option of 50 other cards. You are left with one card with 1.9% possibility and another with 98.1% possibility.
Now if we apply the same thing to the car scenario.
Earlier when you had no information, the probability of you opening the door and getting a car was 1/3 (33.33%)
And the probability of other two doors having the car was 2/3 (66.66%)
When that one door is revealed with the goat, you are left with 1 door with 33.33% probability and another with 66.66% probability.
If you play the door game 300 times:
| Strategy | Rough wins out of 300 | Win rate |
|---|---|---|
| Never switch | ~100 | 33.33% |
| Always switch | ~200 | 66.66% |
The odds are not 50/50.